Why is only (r^2) being even not the final contradiction in the proof of (\sqrt{2})?
Answer and explanation
Correct answer: Because first (r) and then (s) must both be proved even
The contradiction with lowest fraction forms only when numerator and denominator both have common factor (2). Only (r^2) being even is a middle step.
Frequently asked questions
What is the correct answer to this question?
Because first (r) and then (s) must both be proved even
Why is this the correct answer?
The contradiction with lowest fraction forms only when numerator and denominator both have common factor (2). Only (r^2) being even is a middle step.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Proof of irrationality of square root 2 and square root 3.
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