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A student sees \(\sqrt{3}\) displayed as 1.732 on a calculator and claims that \(\sqrt{3}\) is rational because the decimal ends. Which statement correctly identifies the error?

Answer and explanation

Correct answer: 1.732 is only an approximation; the decimal expansion of \(\sqrt{3}\) is non-terminating and non-repeating.

A calculator rounds values to limited digits. Since \(1.732^2=2.999824\ne3\), 1.732 is not exact. It is only an approximation. Exam tip: use exact forms, not calculator displays, to judge rationality.

Related tags

Number SystemsIrrational NumbersSquare Root 3Decimal ExpansionRationality ProofMisconceptionsProof Of Irrationality Of Square Root 2 And Square Root 3Mathematics

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