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Which statement is a wrong conclusion in the proof of \(\sqrt{3}\)?

Answer and explanation

Correct answer: Even if both \(p\) and \(q\) are divisible by \(3\), they are coprime

If both \(p\) and \(q\) are divisible by \(3\), then they have \(3\) as a common factor. Hence, they cannot be coprime. In the irrationality proof of \(\sqrt{3}\), \(p\) and \(q\) are assumed to be coprime; showing that both are divisible by \(3\) gives the required contradiction. Therefore, option C is the wrong conclusion. Exam tip: coprime numbers always have HCF \(1\).

Related tags

Number SystemsSquare Root 3Irrationality ProofCoprime NumbersContradiction ProofProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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