Which statement gives the deeper reason using prime exponents in perfect squares for the proof of (\sqrt{2})?
Answer and explanation
Correct answer: In a perfect square the exponent of (2) is even
In a perfect square every prime exponent is even. In (2b^2), the exponent of (2) becoming odd explains the contradiction.
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What is the correct answer to this question?
In a perfect square the exponent of (2) is even
Why is this the correct answer?
In a perfect square every prime exponent is even. In (2b^2), the exponent of (2) becoming odd explains the contradiction.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Proof of irrationality of square root 2 and square root 3.
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