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Which option correctly distinguishes (q\neq0) and (\gcd(p,q)=1) in the proof of (\sqrt{3})?

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Answer and explanation

Correct answer: (q\neq0) is needed for the fraction and (\gcd(p,q)=1) is the basis of final contradiction

(q\neq0) keeps the fraction defined. (\gcd(p,q)=1) gives contradiction when both are divisible by (3).

Related tags

Number-SystemsDenominatorGcdSqrt3

Frequently asked questions

What is the correct answer to this question?

(q\neq0) is needed for the fraction and (\gcd(p,q)=1) is the basis of final contradiction

Why is this the correct answer?

(q\neq0) keeps the fraction defined. (\gcd(p,q)=1) gives contradiction when both are divisible by (3).

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Proof of irrationality of square root 2 and square root 3.

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