What is the correct difference between the roles of (q\neq0) and (\gcd(p,q)=1) in the proof of (\sqrt{3})?
Answer and explanation
Correct answer: (q\neq0) keeps the fraction defined and (\gcd(p,q)=1) gives final contradiction
(q\neq0) is necessary for a rational fraction. (\gcd(p,q)=1) breaks when both are divisible by (3).
Frequently asked questions
What is the correct answer to this question?
(q\neq0) keeps the fraction defined and (\gcd(p,q)=1) gives final contradiction
Why is this the correct answer?
(q\neq0) is necessary for a rational fraction. (\gcd(p,q)=1) breaks when both are divisible by (3).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Proof of irrationality of square root 2 and square root 3.
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