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In the proof of (\sqrt{2}), if (a,b) are assumed coprime and later (a=2r) and (b=2s) are obtained, which conclusion is most precise?

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Answer and explanation

Correct answer: (\frac{a}{b}) can be reduced to (\frac{r}{s}), so the initial lowest form was impossible

Since both have common factor (2), the fraction can be reduced. This contradicts the coprime lowest form.

Related tags

Number-SystemsExpert-ProofSqrt2Reduction

Frequently asked questions

What is the correct answer to this question?

(\frac{a}{b}) can be reduced to (\frac{r}{s}), so the initial lowest form was impossible

Why is this the correct answer?

Since both have common factor (2), the fraction can be reduced. This contradicts the coprime lowest form.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Proof of irrationality of square root 2 and square root 3.

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