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If c/d is not taken in lowest form in the proof of √2, which conclusion will not remain decisive?

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Answer and explanation

Correct answer: Contradiction when both are even

The governing idea is the role of lowest terms in a contradiction proof. If √2 = c/d, squaring still gives c² = 2d² whether or not the fraction is reduced. The positivity statement √2 > 0 is also unaffected. However, the conclusion that both c and d are even is decisive only when gcd(c,d) = 1 was assumed at the start. Without lowest terms, a fraction may legitimately have an even numerator and denominator, such as 2/4, so their common divisibility is not itself a contradiction. Therefore option A is correct. The other choices describe steps that remain valid independently of reduction.

Related tags

Number-SystemsSqrt2Lowest-TermsProof Of Irrationality Of Square Root 2 And Square Root 3Number SystemsMathematicsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

Contradiction when both are even

Why is this the correct answer?

The governing idea is the role of lowest terms in a contradiction proof. If √2 = c/d, squaring still gives c² = 2d² whether or not the fraction is reduced. The positivity statement √2 > 0 is also unaffected. However, the conclusion that both c and d are even is decisive only when gcd(c,d) = 1 was assumed at the start. Without lowest terms, a fraction may legitimately have an even numerator and denominator, such as 2/4, so their common divisibility is not itself a contradiction. Therefore option A is correct. The other choices describe steps that remain valid independently of reduction.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Proof of irrationality of square root 2 and square root 3.

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