वर्गमूल सर्पिल में \(\sqrt{960}\) को संख्या रेखा पर रखने से पहले कौन-सा अंतराल सही होगा?

Before placing \(\sqrt{960}\) on the number line using a square root spiral, which interval is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(30<\sqrt{960}<31\)

Step 1

Concept

Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them.

Step 2

Why this answer is correct

The correct answer is B. \(30<\sqrt{960}<31\). Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them.

Step 3

Exam Tip

क्योंकि \(30^2=900\) और \(31^2=961\) हैं। (960) इनके बीच है।

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वर्गमूल सर्पिल में \(\sqrt{960}\) को संख्या रेखा पर रखने से पहले कौन-सा अंतराल सही होगा? / Before placing \(\sqrt{960}\) on the number line using a square root spiral, which interval is correct?

Correct Answer: B. \(30<\sqrt{960}<31\). Explanation: क्योंकि \(30^2=900\) और \(31^2=961\) हैं। (960) इनके बीच है। / Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them.

Which concept should I revise for this Mathematics MCQ?

Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them.

What exam hint can help solve this Mathematics question?

क्योंकि \(30^2=900\) और \(31^2=961\) हैं। (960) इनके बीच है।