Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
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Showing 291-300 of 600 questions.
Find the sum of natural numbers from (61) to (75).
B. (1020)
योग \(S_{75}-S_{60}=2850-1830=1020\) है। (61) से शुरू हो तो (60) तक का योग घटाएं। / The sum is \(S_{75}-S_{60}=2850-1830=1020\). If it starts from (61), subtract the sum up to (60).
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A. (31:14)
\(S_{30}:S_{20}=465:210=31:14\)। अनुपात को सरलतम रूप में लिखें। / \(S_{30}:S_{20}=465:210=31:14\). Write the ratio in simplest form.
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If \(S_n=3240\), what will be \(S_{n+1}-S_n\)?
C. (81)
\(3240=S_{80}\), इसलिए \(S_{81}-S_{80}=81\)। अगले योग में अगली संख्या जुड़ती है। / \(3240=S_{80}\), so \(S_{81}-S_{80}=81\). The next sum adds the next number.
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How much is the sum of natural numbers from (81) to (90)?
B. (855)
योग \(S_{90}-S_{80}=4095-3240=855\) है। बड़े योग से पहले का योग घटाएं। / The sum is \(S_{90}-S_{80}=4095-3240=855\). Subtract the previous sum from the larger sum.
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If the sum of the first (n) natural numbers is (2701), what is the value of (n)?
C. (73)
\(\frac{73\cdot74}{2}=2701\), इसलिए (n=73)। विकल्पों को सूत्र में रखकर सत्यापित करें। / \(\frac{73\cdot74}{2}=2701\), so (n=73). Verify the options by substituting them in the formula.
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What is \(\frac{1}{4}\) of the sum of the first (40) natural numbers?
B. (205)
\(S_{40}=820\), इसलिए \(\frac{1}{4}\) भाग (205) है। पहले योग निकालें फिर भाग दें। / \(S_{40}=820\), so \(\frac{1}{4}\) of it is (205). First find the sum and then divide.
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What is the difference between the sums of the first (75) and first (50) natural numbers?
A. (1575)
\(S_{75}-S_{50}=2850-1275=1575\)। यह (51) से (75) तक का योग है। / \(S_{75}-S_{50}=2850-1275=1575\). This is the sum from (51) to (75).
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If \(S_n=4950\), what will (n) be?
B. (99)
\(\frac{99\cdot100}{2}=4950\), इसलिए (n=99)। सम संख्या को आधा कर गणना सरल करें। / \(\frac{99\cdot100}{2}=4950\), so (n=99). Halve the even number to simplify calculation.
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What is the sum of natural numbers from (91) to (100)?
C. (955)
योग \(S_{100}-S_{90}=5050-4095=955\) है। अंतिम (10) संख्याओं का योग घटाव से जल्दी मिलता है। / The sum is \(S_{100}-S_{90}=5050-4095=955\). The sum of the last (10) numbers is quickly found by subtraction.
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If \(S_n=3160\), what will be the value of \(S_n-S_{n-5}\)?
A. (390)
\(3160=S_{79}\), इसलिए \(S_{79}-S_{74}=75+76+77+78+79=385\) नहीं बल्कि सही मान (385) है। विकल्पों को अंतिम गणना से जरूर मिलाएं। / \(3160=S_{79}\), so \(S_{79}-S_{74}=75+76+77+78+79=385\), not (390). Always match options with the final calculation.
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