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If the sum of the first n natural numbers is 2701, what is the value of n?

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Answer and explanation

Correct answer: 73

The governing formula for the sum of the first n natural numbers is Sₙ = n(n + 1)/2. We need n(n + 1)/2 = 2701, or n(n + 1) = 5402. Testing the nearby choices is efficient: for n = 73, the product is 73 × 74 = 5402, and therefore S₇₃ = 73 × 74/2 = 73 × 37 = 2701. Hence n = 73 and option C is correct. The neighboring values do not work: S₇₂ = 72 × 73/2 = 2628, while S₇₄ = 74 × 75/2 = 2775. Since the sum increases strictly as n increases, only one option can satisfy the equation.

Related tags

SequencesProgressionsNatural-NumbersTriangular-NumbersSum Of First N Natural NumbersSequences And ProgressionsMathematicsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

73

Why is this the correct answer?

The governing formula for the sum of the first n natural numbers is Sₙ = n(n + 1)/2. We need n(n + 1)/2 = 2701, or n(n + 1) = 5402. Testing the nearby choices is efficient: for n = 73, the product is 73 × 74 = 5402, and therefore S₇₃ = 73 × 74/2 = 73 × 37 = 2701. Hence n = 73 and option C is correct. The neighboring values do not work: S₇₂ = 72 × 73/2 = 2628, while S₇₄ = 74 × 75/2 = 2775. Since the sum increases strictly as n increases, only one option can satisfy the equation.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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