Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

If (S_n=4950), what will (n) be?

Advertisement

Answer and explanation

Correct answer: 99

The sum of the first n natural numbers is \(S_n=\frac{n(n+1)}{2}\). Thus, \(\frac{n(n+1)}{2}=4950\), so \(n(n+1)=9900\). Since \(99\times100=9900\), \(n=99\). For \(n=100\), the sum would be \(5050\), not 4950. Exam tip: Multiply the given sum by 2 and look for two consecutive numbers whose product equals the result.

Related tags

Sequences And ProgressionsSum Of Natural NumbersArithmetic SeriesQuadratic EquationClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

99

Why is this the correct answer?

The sum of the first n natural numbers is \(S_n=\frac{n(n+1)}{2}\). Thus, \(\frac{n(n+1)}{2}=4950\), so \(n(n+1)=9900\). Since \(99\times100=9900\), \(n=99\). For \(n=100\), the sum would be \(5050\), not 4950. Exam tip: Multiply the given sum by 2 and look for two consecutive numbers whose product equals the result.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement