Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 411-420 of 651 questions.
If \(r=\sqrt{28}+\sqrt{112}\), what is (r) equal to?
A. \(6\sqrt{7}\)
\(\sqrt{28}=2\sqrt{7}\) और \(\sqrt{112}=4\sqrt{7}\) है। इसलिए \(r=6\sqrt{7}\) है। / \(\sqrt{28}=2\sqrt{7}\) and \(\sqrt{112}=4\sqrt{7}\). Therefore \(r=6\sqrt{7}\).
Login to save your score, XP, coins and progress.
Which statement is definitely true about \(\sqrt{8+\sqrt{15}}\)?
B. इसका वर्ग \(8+\sqrt{15}\) हैIts square is \(8+\sqrt{15}\)
क्योंकि \(8+\sqrt{15}\) धनात्मक है, इसका वर्गमूल वास्तविक है। वर्ग करने पर अंदर की संख्या \(8+\sqrt{15}\) मिलती है। / Since \(8+\sqrt{15}\) is positive, its square root is real. Squaring it gives the inside number \(8+\sqrt{15}\).
Login to save your score, XP, coins and progress.
If \(u=\sqrt{125}-\sqrt{45}\) and \(v=\sqrt{5}\), what is the value of (u-v)?
A. \(\sqrt{5}\)
\(\sqrt{125}=5\sqrt{5}\) और \(\sqrt{45}=3\sqrt{5}\), इसलिए \(u=2\sqrt{5}\) है। अतः \(u-v=\sqrt{5}\) है। / \(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\), so \(u=2\sqrt{5}\). Hence \(u-v=\sqrt{5}\).
Login to save your score, XP, coins and progress.
Which is the rationalised form of \(\frac{4}{\sqrt{10}-\sqrt{6}}\)?
A. \(\sqrt{10}+\sqrt{6}\)
संयुग्मी से गुणा करने पर हर (10-6=4) बनता है। इसलिए (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}) है। / Multiplying by the conjugate makes the denominator (10-6=4). So (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}).
Login to save your score, XP, coins and progress.
What is the value of (\(\sqrt{20}+\sqrt{45}\)2)?
A. (125)
\(\sqrt{20}=2\sqrt{5}\) और \(\sqrt{45}=3\sqrt{5}\), इसलिए योग \(5\sqrt{5}\) है। इसका वर्ग (125) है। / \(\sqrt{20}=2\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\), so the sum is \(5\sqrt{5}\). Its square is (125).
Login to save your score, XP, coins and progress.
A. (9), \(2\sqrt{11}\)
(ab=11-2=9) और \(a+b=2\sqrt{11}\) है। संयुग्मी युग्म में गुणन और योग अलग जाँचें। / (ab=11-2=9) and \(a+b=2\sqrt{11}\). In a conjugate pair check product and sum separately.
Login to save your score, XP, coins and progress.
What is the value of (\sqrt{3}\left\(\sqrt{75}-\sqrt{27}\right\))?
A. (6)
\(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए कोष्ठक \(2\sqrt{3}\) है। \(\sqrt{3}\) से गुणा करने पर (6) मिलता है। / \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the bracket is \(2\sqrt{3}\). Multiplying by \(\sqrt{3}\) gives (6).
Login to save your score, XP, coins and progress.
What is the rationalised form of \(\frac{3}{\sqrt{8}+\sqrt{5}}\)?
A. \(\sqrt{8}-\sqrt{5}\)
संयुग्मी से गुणा करने पर हर (8-5=3) बनता है। इसलिए (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}) है। / Multiplying by the conjugate makes the denominator (8-5=3). So (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}).
Login to save your score, XP, coins and progress.
If \(x=3\sqrt{5}-\sqrt{45}\), what is the value of (x)?
A. (0)
\(\sqrt{45}=3\sqrt{5}\), इसलिए \(3\sqrt{5}-3\sqrt{5}=0\) है। पहले मूल को सरल करें। / \(\sqrt{45}=3\sqrt{5}\), so \(3\sqrt{5}-3\sqrt{5}=0\). Simplify the radical first.
Login to save your score, XP, coins and progress.
What is the value of \(\sqrt{4+\sqrt{7}}\times\sqrt{4+\sqrt{7}}\)?
A. \(4+\sqrt{7}\)
एक ही वर्गमूल का अपने आप से गुणन अंदर की संख्या देता है। इसलिए मान \(4+\sqrt{7}\) है। / Multiplying the same square root by itself gives the number inside. Therefore the value is \(4+\sqrt{7}\).
Login to save your score, XP, coins and progress.
Use Google login or mobile OTP. Admin can block users and control login providers.