\(\frac{3}{\sqrt{8}+\sqrt{5}}\) का परिमेयकृत रूप क्या है?

What is the rationalised form of \(\frac{3}{\sqrt{8}+\sqrt{5}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{8}-\sqrt{5}\)

Step 1

Concept

Multiplying by the conjugate makes the denominator (8-5=3). So (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{8}-\sqrt{5}\). Multiplying by the conjugate makes the denominator (8-5=3). So (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (8-5=3) बनता है। इसलिए (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{3}{\sqrt{8}+\sqrt{5}}\) का परिमेयकृत रूप क्या है? / What is the rationalised form of \(\frac{3}{\sqrt{8}+\sqrt{5}}\)?

Correct Answer: A. \(\sqrt{8}-\sqrt{5}\). Explanation: संयुग्मी से गुणा करने पर हर (8-5=3) बनता है। इसलिए (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}) है। / Multiplying by the conjugate makes the denominator (8-5=3). So (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (8-5=3). So (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (8-5=3) बनता है। इसलिए (\frac{3\(\sqrt{8}-\sqrt{5}\)}{3}=\sqrt{8}-\sqrt{5}) है।