\(\frac{4}{\sqrt{10}-\sqrt{6}}\) का परिमेयकृत रूप कौन-सा है?

Which is the rationalised form of \(\frac{4}{\sqrt{10}-\sqrt{6}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{10}+\sqrt{6}\)

Step 1

Concept

Multiplying by the conjugate makes the denominator (10-6=4). So (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{10}+\sqrt{6}\). Multiplying by the conjugate makes the denominator (10-6=4). So (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (10-6=4) बनता है। इसलिए (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{4}{\sqrt{10}-\sqrt{6}}\) का परिमेयकृत रूप कौन-सा है? / Which is the rationalised form of \(\frac{4}{\sqrt{10}-\sqrt{6}}\)?

Correct Answer: A. \(\sqrt{10}+\sqrt{6}\). Explanation: संयुग्मी से गुणा करने पर हर (10-6=4) बनता है। इसलिए (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}) है। / Multiplying by the conjugate makes the denominator (10-6=4). So (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (10-6=4). So (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (10-6=4) बनता है। इसलिए (\frac{4\(\sqrt{10}+\sqrt{6}\)}{4}=\sqrt{10}+\sqrt{6}) है।