What is obtained by taking out the common factor from (12p^2q-8pq^2)?
The greatest common factor is (4pq). Exam tip: find common variables and numbers in every term.
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SubjectsMathematics
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The greatest common factor is (4pq). Exam tip: find common variables and numbers in every term.
View question details(4=2^2) and (-4z=-2\times z\times2), so it is ((z-2)^2). Exam tip: identify subtraction perfect squares.
View question detailsUsing \((a-b)^2=a^2-2ab+b^2\), take \(a=5p\) and \(b=2\). The middle term is \(-2\times5p\times2=-20p\), so the expansion is \(25p^2-20p+4\). Exam tip: always check the sign of the middle term.
View question details(2+3=5) and (2\times3=6), so the factors are correct. Exam tip: check factors of the last term.
View question detailsThis expression is a difference of squares: \(16n^2=(4n)^2\) and \(25=5^2\). Using \(a^2-b^2=(a-b)(a+b)\), we get \(16n^2-25=(4n-5)(4n+5)\). Expanding \((16n-5)(16n+5)\) gives \(256n^2-25\), so it is not correct. Exam tip: identify the square roots of both terms before applying the difference-of-squares formula.
View question detailsThe greatest common factor of (8x) and (12) is (4). Exam tip: take the greatest factor for the simplest form.
View question details(9x^2=(3x)^2), (1=1^2), and (6x=2\times3x\times1). Exam tip: match the perfect square pattern.
View question detailsIn \(x^2+6x+9\), the first and last terms are \(x^2\) and \(3^2\), while the middle term is \(2\times x\times3=6x\). Hence it is \((x+3)^2\). In \(x^2+6x+8\), the constant term is not \(3^2\). Exam tip: check whether the middle term equals \(2ab\).
View question detailsSince \(36=6^2\), the required form is \((x+6)^2=x^2+2\times6x+36=x^2+12x+36\). Hence, \(b=12\). For \(b=6\), the middle term is not twice the square root of 36. Exam tip: double the square root of the constant term.
View question detailsBoth terms of \(7x^2+21x\) are divisible by \(7x\): \(7x^2\div7x=x\) and \(21x\div7x=3\). Hence it factorises as \(7x(x+3)\). In B, the constant term 7 has no \(x\). Exam tip: check every term.
View question detailsA perfect-square trinomial has the form \(a^2+2ab+b^2\). Here, \(x^2+10x+25=x^2+2\cdot x\cdot5+5^2=(x+5)^2\). In option B, the constant term would need to be \(25\). Exam tip: check whether the middle term equals twice the product of the square roots of the first and last terms.
View question detailsUsing the distributive property, multiply 5 by both terms: \(5\times3a=15a\) and \(5\times(-4)=-20\). Hence \(5(3a-4)=15a-20\). Exam tip: expand the bracket to check a factorisation.
View question detailsUsing \(a^2+2ab+b^2=(a+b)^2\), put \(a=m\) and \(b=n\). Thus, \(m^2+2mn+n^2=(m+n)^2\). Expanding \((m-n)^2\) gives the middle term \(-2mn\), so it is not correct. Exam tip: use the sign of the middle term to distinguish \((a+b)^2\) from \((a-b)^2\).
View question details(-2-4=-6) and ((-2)\times(-4)=8). Exam tip: for positive last term and negative middle term, take both signs negative.
View question detailsThe greatest common factor of (18xy) and (24y) is (6y). Exam tip: check numbers and variables together.
View question detailsSince (1=1^2), (x^2-1) is a difference of squares. Exam tip: apply small identities carefully.
View question detailsIn \(x^2+14x+49\), \(49=7^2\) and the middle term is \(2\times x\times7=14x\). Hence it is \((x+7)^2\). In exams, check whether the middle term matches \(2ab\).
View question details(1+5=6) and (1\times5=5), so the correct pair is (1) and (5). Exam tip: match sum and product.
View question details(36p^2=(6p)^2) and (49q^2=(7q)^2). Exam tip: form factors from square roots of both squares.
View question detailsThe greatest common factor in both terms is (5xy). Exam tip: keep the inside terms simplified.
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