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Which of the following expressions can be factorised as the square of a binomial?
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Answer and explanation
Correct answer: \(x^2+6x+9\)
In \(x^2+6x+9\), the first and last terms are \(x^2\) and \(3^2\), while the middle term is \(2\times x\times3=6x\). Hence it is \((x+3)^2\). In \(x^2+6x+8\), the constant term is not \(3^2\). Exam tip: check whether the middle term equals \(2ab\).
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What is the correct answer to this question?
\(x^2+6x+9\)
Why is this the correct answer?
In \(x^2+6x+9\), the first and last terms are \(x^2\) and \(3^2\), while the middle term is \(2\times x\times3=6x\). Hence it is \((x+3)^2\). In \(x^2+6x+8\), the constant term is not \(3^2\). Exam tip: check whether the middle term equals \(2ab\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
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