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For which value of \(b\) will the polynomial \(x^2+bx+36\) be a perfect-square trinomial?
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Answer and explanation
Correct answer: 12
Since \(36=6^2\), the required form is \((x+6)^2=x^2+2\times6x+36=x^2+12x+36\). Hence, \(b=12\). For \(b=6\), the middle term is not twice the square root of 36. Exam tip: double the square root of the constant term.
Frequently asked questions
What is the correct answer to this question?
12
Why is this the correct answer?
Since \(36=6^2\), the required form is \((x+6)^2=x^2+2\times6x+36=x^2+12x+36\). Hence, \(b=12\). For \(b=6\), the middle term is not twice the square root of 36. Exam tip: double the square root of the constant term.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
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