Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 71-80 of 600 questions.
How many distinct arrangements are there for the word (MOM)?
A. (3)
(M) दो बार है इसलिए \(\frac{3!}{2!}=3\) arrangements हैं। समान अक्षर होने पर कुल arrangements घट जाती हैं। / (M) occurs twice, so there are \(\frac{3!}{2!}=3\) arrangements. Repeated letters reduce total arrangements.
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In how many ways can (4) children from (6) children be made to stand in the front row?
C. (360)
उत्तर \({}^{6}P_{4}=6\times5\times4\times3=360\) है। पंक्ति में क्रम महत्त्वपूर्ण होता है। / The answer is \({}^{6}P_{4}=6\times5\times4\times3=360\). Order matters in a row.
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How many (3)-digit numbers can be formed from digits (1,4,7,8,9) without repetition?
D. (60)
तीन स्थानों के लिए \(5\times4\times3=60\) तरीके हैं। बिना पुनरावृत्ति में हर अगला विकल्प कम होता है। / For three places, there are \(5\times4\times3=60\) ways. Without repetition, each next choice decreases.
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What is the value of \({}^{7}P_{0}\)?
A. (1)
\({}^{n}P_{0}=1\) होता है इसलिए \({}^{7}P_{0}=1\)। शून्य वस्तु चुनने का एक ही तरीका माना जाता है। / \({}^{n}P_{0}=1\), so \({}^{7}P_{0}=1\). Choosing zero objects is counted in one way.
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In how many ways can (4) different labels be pasted on (4) different boxes?
B. (24)
(4) अलग लेबल (4) अलग डिब्बों पर (4!=24) तरीकों से लगेंगे। matching arrangements में factorial काम आता है। / (4) different labels can be pasted on (4) different boxes in (4!=24) ways. Factorial is useful in matching arrangements.
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The word (SCHOOL) has (O) twice. How many distinct letter arrangements are possible?
C. (360)
कुल (6) अक्षर हैं और (O) दो समान हैं इसलिए \(\frac{6!}{2!}=360\)। repeated letter के लिए denominator लगाएं। / There are (6) letters and two identical (O)'s, so \(\frac{6!}{2!}=360\). Use a denominator for a repeated letter.
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How many ways are there to choose an ordered trip of (2) cities from (5) different cities?
D. (20)
पहले शहर के लिए (5) और दूसरे के लिए (4) विकल्प हैं इसलिए (20)। यात्रा क्रम बदलने से योजना बदलती है। / There are (5) choices for the first city and (4) for the second, so (20). Changing trip order changes the plan.
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How many (3)-digit numbers can be formed from digits (0,1,2,3) without repetition?
A. (18)
सैकड़ा स्थान पर (3) विकल्प हैं, फिर (3) और (2) विकल्प हैं, कुल (18)। पहले स्थान पर (0) न रखें। / There are (3) choices for the hundreds place, then (3) and (2) choices, total (18). Do not put (0) in the first place.
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In how many ways can (3) distinct red, blue and green flags be placed on a pole from top to bottom?
B. (6)
(3) अलग झंडों की क्रमबद्ध व्यवस्था (3!=6) है। ऊपर-नीचे का क्रम बदलने से arrangement बदलती है। / The ordered arrangement of (3) distinct flags is (3!=6). Changing top-bottom order changes the arrangement.
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In how many ways can a president and secretary be chosen from (11) candidates?
C. (110)
दो पद अलग हैं इसलिए \({}^{11}P_{2}=11\times10=110\)। अलग पदों के लिए क्रमचय लगाएं। / The two posts are distinct, so \({}^{11}P_{2}=11\times10=110\). Use permutation for distinct posts.
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