Cutting of DNA

Correct answer: A. To provide correct pH salt and cofactors for enzyme

Restriction enzymes work best in defined buffer conditions. Wrong buffer can give incomplete digestion.

Correct answer: A. As a cofactor for enzyme activity

Magnesium ion helps catalytic activity of many restriction enzymes. Required ions are provided in buffer.

Correct answer: A. To control enzyme exposure and timing

Other components are mixed at correct concentration first. Adding enzyme last gives better reaction timing control.

Correct answer: A. Enzyme may become insufficient and give incomplete digestion

The direct answer is A: too much DNA can make the available enzyme insufficient and lead to incomplete digestion. Restriction digestion depends on a suitable ratio between DNA amount and active enzyme units, together with the correct buffer, temperature, and time. Step by step: the enzyme has a limited catalytic capacity; if the DNA amount is increased greatly while enzyme units and reaction time remain unchanged, not every recognition site may be cut; undigested or partially digested molecules can then remain. Option A is correct. Option B is wrong because adding more DNA does not make the enzyme double; enzyme quantity does not increase automatically. Option C is wrong because restriction digestion does not convert DNA into protein; protein formation is a separate gene-expression process involving transcription and translation. Option D is wrong because buffer does not simply vanish when DNA is added, although an unsuitable DNA or sample volume can disturb the reaction conditions. Use the recommended DNA mass, enzyme units, buffer, and incubation time. A useful cue is to balance substrate, enzyme, and conditions rather than assuming that more DNA always gives a stronger result.

Correct answer: A. The band may be very faint

The governing concept is detection sensitivity in agarose-gel electrophoresis. DNA bands become visible because enough stained DNA accumulates in a narrow region to produce a detectable signal. If the reaction contains or the gel lane receives too little DNA, the resulting signal may be weak, so the band can appear faint or may be difficult to see. Option A is correct. A bright band requires sufficient DNA and suitable staining conditions; it is not guaranteed. Low DNA does not prevent the gel from running because electrophoresis depends mainly on the gel, buffer, electrodes, and applied voltage. The enzyme statement is biologically and procedurally unrelated.

Correct answer: A. Very long incubation can cause non-specific DNA cleavage (star activity)

A is correct. Restriction digestion is usually completed within the recommended incubation time. Excessively long incubation, especially under non-optimal conditions, may allow the enzyme to cut DNA at sequences similar to its normal recognition site. This non-specific cleavage is called star activity and can produce unwanted DNA fragments. Extra time does not increase enzyme concentration, convert sticky ends into blunt ends, or purify DNA. Exam tip: For digestion, follow the prescribed enzyme, buffer, temperature, and incubation time together.

Correct answer: A. In wrong buffer excess enzyme or long incubation

The direct answer is A: star activity can increase in the wrong buffer, with excess enzyme, or after excessively long incubation. A restriction enzyme normally recognizes a particular DNA sequence and cuts there. Under unsuitable conditions, its recognition becomes less strict, so it may cut at similar but non-target sites. Step by step: first, the enzyme is mixed with DNA and buffer; second, the buffer controls salt, pH, and other conditions; third, too much enzyme or too much time increases opportunities for incorrect cutting; therefore extra, unwanted bands may appear. A is correct because it lists known causes. B is wrong because perfect recommended conditions usually reduce star activity, not always increase it. C is wrong because without enzyme no enzyme-mediated star cutting can occur. D is wrong because without DNA there is no substrate to cut. Memory cue: “wrong conditions make relaxed cutting.” Follow the protocol, use the correct buffer and enzyme amount, and avoid unnecessary over-incubation.

Correct answer: A. In partial digestion not all sites cut and in star activity wrong sites may cut

Partial digestion is incomplete cutting. Star activity can give extra cutting due to reduced specificity.

Correct answer: A. Methylation can block recognition or cutting

Some enzymes do not cut methylated recognition sites. Therefore methylation sensitivity must be checked.

Correct answer: A. bacterial DNA methylation / Bacterial DNA methylation

Dam and Dcm refer to DNA methylation systems found in bacteria. Dam methylation commonly modifies adenine in particular recognition sequences, while Dcm methylation modifies cytosine in particular sequences. The methyl groups can affect whether a restriction enzyme recognizes or cuts a site, because some restriction enzymes are sensitive to the methylation state of their recognition sequence.

Therefore option A, bacterial DNA methylation, is correct. The terms do not describe gel colour, protein folding, or the boiling of ethanol. In a restriction-digestion experiment, the bacterial strain from which DNA was obtained can matter because its methylation pattern may change the digestion pattern. This is why methylation should be considered when an expected restriction fragment is missing or altered.

Correct answer: A. DNA source and methylation status

Methylated DNA can block enzyme cutting. Therefore a suitable host strain or alternative enzyme can be chosen.

Correct answer: A. When enzyme must be stopped before next step

Heat inactivation can stop activity of some enzymes. Always check enzyme-specific instructions.

Correct answer: A. Each restriction enzyme has different heat stability

Restriction enzymes are proteins, and their structures and heat stabilities differ. Some are denatured and inactivated at a suitable high temperature, whereas others are relatively heat-stable; therefore, heat treatment cannot inactivate every restriction enzyme. Option C is incorrect because excessive heat usually disrupts enzyme structure rather than universally increasing activity. Exam tip: Check the recommended inactivation temperature and incubation time for a particular enzyme.

Correct answer: A. Removing enzyme, buffer salts, and small fragments

The governing concept is purification of a DNA sample before a downstream molecular-biology reaction. Restriction digestion mixtures contain the desired DNA fragments together with enzyme, buffer components, salts, and sometimes very small unwanted fragments. Cleanup removes or reduces these contaminants, improving DNA purity and making later steps such as ligation, cloning, or amplification more reliable. Option A is correct because it describes the practical purpose of the cleanup. Cleanup is intended to preserve and recover useful DNA, not destroy it. It does not synthesize protein, and staining agar is a separate gel-visualization operation unrelated to purification of the digestion mixture.

Correct answer: A. To separate the desired DNA fragment from other DNA fragments

In gel extraction, the desired DNA band is excised from an agarose gel and the DNA is purified from it. Therefore, it is needed when digestion produces several DNA fragments and the correct insert must be isolated for cloning. It does not colour restriction enzymes or freeze buffers. Exam tip: remember that gel extraction purifies a specific DNA fragment from a gel band.

Correct answer: A. Because binding, washing, or elution may be incomplete

The governing concept is recovery efficiency during purification. In gel extraction, the desired DNA band is cut from agarose, dissolved or processed, bound to a purification membrane, washed, and finally eluted. At each stage some DNA can remain in the gel, fail to bind efficiently, be lost during washing, or remain on the membrane instead of entering the elution buffer. Consequently, recovery is usually less than 100%, and careless band excision or incomplete elution can increase the loss. Option A correctly identifies these causes. DNA does not automatically multiply during extraction, agarose does not make protein, and enzyme formation is unrelated.

Correct answer: A. DNA damage

UV radiation from a transilluminator can damage DNA by causing lesions such as strand breaks or thymine dimers. Therefore, UV exposure should be kept as short as possible while cutting a gel band, especially if the DNA will be used later for ligation or cloning. A brighter band does not mean that the amount of DNA has increased. Exam tip: prolonged UV exposure is associated with DNA damage.

Correct answer: A. It can reduce UV damage

The governing concept is safer visualization of DNA bands after gel electrophoresis. Conventional ultraviolet illumination can damage DNA through UV-induced lesions, which is undesirable when the band will be recovered for cloning, sequencing, or another downstream application. A blue-light transilluminator uses visible blue light and can reduce such photodamage compared with UV exposure, although appropriate fluorescent stains and instrument settings are still required. Therefore option A is correct. Blue light does not convert DNA into protein, does not make an enzyme permanently inactive, and does not dissolve the agarose gel. Its main benefit is improved preservation of recoverable DNA.

Correct answer: A. To help load the sample into wells and track DNA migration

Gel loading dye commonly contains glycerol or sucrose, which makes the sample denser so that it settles into the agarose-gel well. It also contains tracking dyes that help monitor the progress of DNA migration during electrophoresis. DNA is cut by a restriction enzyme, not by the loading dye. Exam tip: remember the two key roles of loading dye—easy loading and migration tracking.

Correct answer: A. expected fragment size range / Expected fragment size range

Different agarose percentages separate different size ranges better. Choose gel according to fragment size.

Correct answer: A. It forms smaller pores and resolves small DNA fragments better

Increasing the agarose percentage makes the pores of the gel smaller. Small DNA fragments are separated more clearly according to their size in such a gel, giving better resolution. Option B is incorrect because a higher agarose concentration generally slows DNA migration rather than increasing its speed. Exam tip: remember that high-percentage agarose is preferred for small fragments, whereas low-percentage agarose is used for larger fragments.

Correct answer: A. It forms larger pores, allowing easier migration of large DNA fragments

A gel with a lower agarose percentage has larger pores. Therefore, large DNA fragments face less resistance while moving through the gel matrix and can be separated more effectively. In contrast, higher-percentage agarose has smaller pores and is more suitable for smaller fragments. Exam tip: choose low-percentage agarose for large DNA fragments.

Correct answer: A. To compare sample fragment sizes with known standards

The governing concept is electrophoretic size estimation. A DNA ladder contains fragments of previously known lengths and is loaded in a separate lane beside the digested sample. Because DNA fragments move through agarose gel according to size, the position of an unknown band can be compared with nearby ladder bands. This gives an approximate fragment length and helps determine whether the restriction digest produced the expected pattern. The ladder does not perform digestion, methylation, or heating; those actions are unrelated to its role. Therefore, comparing fragment sizes with known standards is the correct reason for using the ladder lane.

Correct answer: A. Due to plasmid conformations like supercoiled open circular and linear

Uncut plasmid can migrate in different conformations. After digestion the linear band appears differently.

Correct answer: A. Its conformation is not compact

The direct answer is A: an open circular plasmid is not as compact as a supercoiled plasmid, so it can migrate differently through an agarose gel. Plasmid DNA can exist in different conformations. A supercoiled molecule is tightly folded, while a nick in one strand relaxes the molecule into an open circular form. During electrophoresis, DNA moves through the gel according to charge, size, and especially shape. Step by step: both molecules are DNA and carry negative charge; their shapes differ; the gel offers resistance differently to each shape; therefore their migration distances need not be the same. A is correct. B is wrong because an open circular plasmid is still DNA, not RNA. C is wrong because plasmid is nucleic acid, not protein. D is wrong because DNA has a negatively charged phosphate backbone. The exact order of conformations can depend on conditions, so compare bands with suitable controls. Memory cue: “same DNA, different shape, different movement.”