Cutting of DNA

Correct answer: A. Restriction enzymes cut DNA at specific sites to make fragments

Restriction enzymes work like molecular scissors. Sticky or blunt ends are useful in recombinant DNA formation.

Correct answer: A. Cutting at all target sites

In complete digestion the enzyme cuts all recognition sites. The expected fragment pattern appears on gel.

Correct answer: C. Too little restriction enzyme or insufficient incubation time

If the amount of restriction enzyme is too low or the incubation time is insufficient, all recognition sites on the DNA may not be cut. As a result, some DNA molecules are cut completely while others are cut only at some sites, producing partial digestion. DNA ligase joins DNA fragments; it does not cut them. Exam tip: For partial digestion, check enzyme amount, incubation time, and suitable buffer conditions.

Correct answer: D. Cutting at similar sites besides the normal site

Direct answer: option D, cutting at sites similar to the normal recognition site. Restriction enzymes usually recognise a particular DNA sequence and cut it specifically. Under unsuitable reaction conditions, their specificity can decrease; the enzyme may then cut at sequences that resemble, but are not exactly, the normal site. This unusual relaxed specificity is called star activity. Option A, enzyme storage only, describes handling and has nothing to do with altered DNA recognition. Option B, DNA ligation only, means joining DNA fragments and is a different enzymatic process. Option C, protein staining only, concerns visualising proteins, not restriction digestion. Option D correctly describes extra cutting at similar sites. Star activity can be encouraged by too much enzyme, excessive reaction time, unsuitable buffer or other non-ideal conditions. In careful experiments, use the recommended buffer, enzyme amount and incubation time. Memory cue: star activity means the restriction enzyme becomes less strict about its target sequence.

Correct answer: A. Use recommended buffer and correct enzyme amount

The direct answer is A: use the recommended buffer and the correct amount of enzyme. Star activity means that a restriction enzyme loses its usual sequence specificity and cuts at sites that are similar to, but not exactly, its normal recognition site. Step by step, the enzyme needs the correct pH, salt concentration, temperature, reaction volume, and DNA-to-enzyme ratio. Therefore, use the manufacturer-recommended buffer, avoid adding excessive enzyme, do not incubate unnecessarily for too long, and keep the reaction conditions suitable. Option A is correct because these steps preserve accurate cutting. Option B is wrong because sunlight can damage or inactivate the enzyme. Option C is wrong because always boiling DNA can damage it and does not prevent star activity. Option D is wrong because salt must not simply be removed in every reaction; the correct salt concentration is needed, and excessive salt or unsuitable conditions are the real concerns. Exam cue: star activity usually points to non-ideal reaction conditions, excess enzyme, or excessive incubation.

Correct answer: D. To maintain activity of both enzymes

Two enzymes can show different efficiencies in the same buffer. Compatible buffer is necessary for digestion success.

Correct answer: A. When two enzymes do not work well in one buffer

In sequential digestion enzymes are used in separate steps. It helps when buffers are incompatible.

Correct answer: A. If they produce same or compatible overhangs

The direct answer is option A: different enzymes can produce compatible sticky ends when their overhangs are the same or can base-pair with each other. A restriction enzyme cuts DNA and may leave a short single-stranded overhang called a sticky end. Two ends are compatible if their exposed bases can pair correctly, allowing DNA ligase to join them. The recognition sequences used by the enzymes may be different, but the important point is the sequence and direction of the overhang. Option A is correct because same or compatible overhangs can anneal and then be sealed by ligase. Option B is wrong: DNA cannot have no bases and still provide a meaningful sticky end. Option C is wrong because the mere presence of protein does not make DNA ends compatible. Option D is irrelevant: melting a gel does not create matching DNA overhangs. The memory cue is: different cutters may still be useful if their sticky ends match.

Correct answer: B. Enzymes cutting at different positions within the same recognition sequence

The direct answer is option B: neoschizomers are restriction enzymes that recognize the same DNA sequence but cut at different positions within that sequence. First distinguish recognition from cutting: an enzyme identifies a particular base sequence, then cuts the DNA at a specified location. In neoschizomers, the recognition sequence is the same, but the cut locations differ, so the ends produced may differ. Option B is correct because it gives both defining features. Option A is wrong because starch-digesting enzymes are amylases, not neoschizomers. Option C is wrong because enzymes that join DNA are ligases, whereas restriction enzymes cut DNA. Option D is wrong because lipid-making enzymes have no connection with this restriction-enzyme classification. A careful student should not assume that the same recognition sequence always means the same cut position. Memory cue: “neo” means new or different here—the site is the same, but the cut is different.

Correct answer: C. Map showing the positions of restriction enzyme cut sites in DNA

A restriction map shows the positions, order, and often the distances between restriction enzyme cut sites on a DNA molecule. Therefore, option C is correct. It does not show gene functions; that relates to gene mapping or functional annotation. Exam tip: remember a restriction map as a map of DNA cutting sites.

Correct answer: D. Checking whether clone or insert is correct

Diagnostic digestion confirms a construct using expected bands. It is common in cloning verification.

Correct answer: A. The construct may be correct

Expected bands indicate the correct insert according to vector map. Sequencing is also useful for final confirmation.

Correct answer: B. Wrong clone or incomplete digestion

Unexpected bands can show wrong construct partial digestion or star activity. Troubleshooting is needed.

Correct answer: C. Amount of activity to cut DNA under defined condition

Enzyme units describe activity. Enzyme amount is chosen according to DNA amount in reaction setup.

Correct answer: D. Star activity or glycerol effect

Excess enzyme can disturb reaction conditions and increase star activity. Use recommended amount.

Correct answer: A. For enzyme stability and freezing protection

The direct answer is A: glycerol helps maintain enzyme stability and protects the enzyme during freezing. Restriction enzymes are commonly stored at very low temperatures. Pure or poorly protected protein can be damaged by freezing and thawing, but glycerol helps reduce this damage and also keeps the enzyme preparation stable. Step by step: the enzyme is mixed with a storage solution containing glycerol; the glycerol lowers the harmful effect of ice formation; the enzyme therefore remains usable during frozen storage. Option A is correct for these stability and freeze-protection roles. Option B is wrong because glycerol itself does not cut DNA; the restriction enzyme performs the cutting. Option C is wrong because gel staining is done with suitable DNA-binding stains after electrophoresis, not by storage glycerol. Option D is wrong because RNA synthesis requires polymerases and other appropriate components, not glycerol in a restriction-enzyme storage buffer. A useful caution is that too much glycerol carried into the digestion reaction may interfere with enzyme specificity, so the recommended reaction conditions should be followed.

Correct answer: A. Enzyme activity can decrease

A restriction enzyme is a protein. Repeated freezing and thawing can destabilize its structure and reduce its ability to cut DNA. Doubling the amount of DNA occurs through amplification methods such as PCR, not through freeze-thaw cycles. Exam tip: restriction enzymes are commonly stored in small aliquots to avoid repeated freeze-thawing.

Correct answer: B. To control enzyme exposure after reaction conditions are ready

Adding enzyme last ensures reaction conditions are correct first. It helps control activity and timing.

Correct answer: C. To prevent unwanted DNA degradation

Nuclease-free water does not contain contaminating nucleases such as DNases. Such enzymes can cut or degrade DNA at unwanted sites and interfere with the restriction digestion result. Therefore, option C is correct because it protects DNA from unwanted degradation. The restriction enzyme itself cuts DNA only at its specific recognition site; water is not used to cut DNA. Exam tip: Use nuclease-free reagents in DNA-based reactions to prevent contamination and DNA damage.

Correct answer: D. To prevent contamination and nuclease entry

Clean, sterile pipette tips prevent the entry of foreign DNA, microorganisms, or nucleases such as DNase into the sample. Nucleases can cut or degrade DNA and may give incorrect restriction digestion results. Agarose gel is prepared in a separate step to separate DNA fragments, so option B is not the reason. Exam tip: When handling DNA and restriction enzymes, remember to use sterile, preferably filter, tips.

Correct answer: A. Ethanol can inhibit enzyme reaction

Residual ethanol can reduce restriction enzyme activity. The DNA pellet should be dried properly.

Correct answer: A. Methylation can block enzyme recognition

Some enzymes do not cut methylated recognition sites. Methylation sensitivity should be checked in enzyme choice.

Correct answer: A. Its cutting can change at methylated site

Methylation-sensitive enzymes may cut methylated DNA poorly or not at all. This can change digestion pattern.

Correct answer: A. The DNA that enzyme will cut

Substrate DNA is the cutting target in the reaction. The enzyme looks for recognition site on this DNA.

Correct answer: A. Their shape and cut site arrangement differ

Circular DNA can become linear with one cut while linear DNA can show different fragment counts. Shape affects pattern.