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sum MCQ Questions for Class 10

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93 questions tagged with sum.

Question 91/93 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि किसी बहुपद के ग्राफ के (x)-अक्ष कटान ((r,0)), ((s,0)), ((t,0)) हैं, तो शून्यकों का योग क्या होगा?

If the (x)-axis intersections of a polynomial graph are ((r,0)), ((s,0)), ((t,0)), what will be the sum of the zeroes?

Explanation opens after your attempt
Correct Answer

A. (r+s+t)

Step 1

Concept

The zeroes are the first coordinates (r), (s), (t). Tip: read the first coordinate even in symbolic points.

Step 2

Why this answer is correct

The correct answer is A. (r+s+t). The zeroes are the first coordinates (r), (s), (t). Tip: read the first coordinate even in symbolic points.

Step 3

Exam Tip

शून्यक पहले निर्देशांक (r), (s), (t) हैं। टिप: प्रतीकात्मक बिंदुओं में भी पहला निर्देशांक पढ़ें।

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Question 92/93 Hard Mathematics Real Numbers HCF and LCM using prime factorisation Class 10 Level 13

यदि \(176=2^4\times11\) और \(264=2^3\times3\times11\), तो इनके महत्तम समापवर्तक और लघुत्तम समापवर्त्य का योग क्या होगा?

If \(176=2^4\times11\) and \(264=2^3\times3\times11\), what is the sum of their HCF and LCM?

Explanation opens after your attempt
Correct Answer

B. (616)

Step 1

Concept

HCF \(=2^3\times11=88\).

Step 2

Why this answer is correct

LCM \(=2^4\times3\times11=528\), so the sum is (88+528=616).

Step 3

Exam Tip

When sum is asked, find both values separately. चरण 1: महत्तम समापवर्तक \(2^3\times11=88\) है। चरण 2: लघुत्तम समापवर्त्य \(2^4\times3\times11=528\) है, इसलिए योग (88+528=616) है। चरण 3: योग पूछे जाने पर दोनों मान अलग-अलग निकालें।

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Question 93/93 Hard Mathematics Real Numbers HCF and LCM using prime factorisation Class 10 Level 12

यदि \(165=3\times5\times11\) और \(231=3\times7\times11\), तो इनके महत्तम समापवर्तक और लघुत्तम समापवर्त्य का योग क्या होगा?

If \(165=3\times5\times11\) and \(231=3\times7\times11\), what is the sum of their HCF and LCM?

Explanation opens after your attempt
Correct Answer

C. (1188)

Step 1

Concept

The common prime factors are (3) and (11), so HCF (=33).

Step 2

Why this answer is correct

LCM \(=3\times5\times7\times11=1155\), so the sum is (33+1155=1188).

Step 3

Exam Tip

When sum is asked, find both values separately. चरण 1: समान अभाज्य गुणनखंड (3) और (11) हैं, इसलिए महत्तम समापवर्तक (33) है। चरण 2: लघुत्तम समापवर्त्य \(3\times5\times7\times11=1155\) है, इसलिए योग (33+1155=1188) है। चरण 3: योग पूछे जाने पर दोनों मान अलग-अलग निकालें।

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