Concept-wise Practice

sqrt6 MCQ Questions for Class 10

sqrt6 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with sqrt6.

\(\sqrt{384}+\sqrt{54}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{384}+\sqrt{54}\)?

Explanation opens after your attempt
Correct Answer

A. \(11\sqrt{6}\)

Step 1

Concept

\(\sqrt{384}=8\sqrt{6}\) and \(\sqrt{54}=3\sqrt{6}\).

Step 2

Why this answer is correct

\(8\sqrt{6}+3\sqrt{6}=11\sqrt{6}\).

Step 3

Exam Tip

Add radicals only after they become like radicals. चरण 1: \(\sqrt{384}=8\sqrt{6}\) और \(\sqrt{54}=3\sqrt{6}\)। चरण 2: \(8\sqrt{6}+3\sqrt{6}=11\sqrt{6}\)। चरण 3: समान वर्गमूल बनने के बाद ही उन्हें जोड़ें।

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\(\sqrt{216}+\sqrt{54}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{216}+\sqrt{54}\)?

Explanation opens after your attempt
Correct Answer

A. \(9\sqrt{6}\)

Step 1

Concept

\(\sqrt{216}=6\sqrt{6}\) and \(\sqrt{54}=3\sqrt{6}\).

Step 2

Why this answer is correct

\(6\sqrt{6}+3\sqrt{6}=9\sqrt{6}\).

Step 3

Exam Tip

Add radicals only after they become like radicals. चरण 1: \(\sqrt{216}=6\sqrt{6}\) और \(\sqrt{54}=3\sqrt{6}\)। चरण 2: \(6\sqrt{6}+3\sqrt{6}=9\sqrt{6}\)। चरण 3: समान वर्गमूल बनने के बाद ही उन्हें जोड़ें।

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\(\sqrt{150}+\sqrt{24}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{150}+\sqrt{24}\)?

Explanation opens after your attempt
Correct Answer

A. \(7\sqrt{6}\)

Step 1

Concept

\(\sqrt{150}=5\sqrt{6}\) and \(\sqrt{24}=2\sqrt{6}\).

Step 2

Why this answer is correct

\(5\sqrt{6}+2\sqrt{6}=7\sqrt{6}\).

Step 3

Exam Tip

Add radicals only after they become like radicals. चरण 1: \(\sqrt{150}=5\sqrt{6}\) और \(\sqrt{24}=2\sqrt{6}\)। चरण 2: \(5\sqrt{6}+2\sqrt{6}=7\sqrt{6}\)। चरण 3: समान वर्गमूल बनने के बाद ही जोड़ें।

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\(\sqrt{6}\) का दशमलव विस्तार कैसा होगा?

What kind of decimal expansion does \(\sqrt{6}\) have?

Explanation opens after your attempt
Correct Answer

C. अनवसानी और अनावर्तीNon-terminating and non-recurring

Step 1

Concept

(6) is not a perfect square.

Step 2

Why this answer is correct

So \(\sqrt{6}\) is irrational and its decimal is non-terminating and non-recurring.

Step 3

Exam Tip

An irrational number has no fixed repeating pattern. चरण 1: (6) पूर्ण वर्ग नहीं है। चरण 2: इसलिए \(\sqrt{6}\) अपरिमेय है और इसका दशमलव अनवसानी अनावर्ती होगा। चरण 3: अपरिमेय संख्या में स्थिर दोहराव नहीं होता।

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