\(-\frac{22}{7}\) is about (-3.14), so it lies between (-4) and (-3). In exams, note the order of negative decimals.
Step 2
Why this answer is correct
The correct answer is B. (-4) और (-3) / (-4) and (-3). \(-\frac{22}{7}\) is about (-3.14), so it lies between (-4) and (-3). In exams, note the order of negative decimals.
Step 3
Exam Tip
\(-\frac{22}{7}\) लगभग (-3.14) है, इसलिए यह (-4) और (-3) के बीच है। परीक्षा में ऋणात्मक दशमलव का क्रम ध्यान रखें।
\(\frac{19}{6}=3+\frac{1}{6}\), so it lies between (3) and (4). In exams, divide to identify the whole part.
Step 2
Why this answer is correct
The correct answer is B. (3) और (4) / (3) and (4). \(\frac{19}{6}=3+\frac{1}{6}\), so it lies between (3) and (4). In exams, divide to identify the whole part.
Step 3
Exam Tip
\(\frac{19}{6}=3+\frac{1}{6}\), इसलिए यह (3) और (4) के बीच है। परीक्षा में भाग देकर पूर्ण भाग पहचानें।
C. \(-\sqrt{2}\) (0) के बाईं ओर है/\(-\sqrt{2}\) is to the left of (0)
Step 1
Concept
\(-\sqrt{2}\) is negative, so it lies to the left of (0). In exams, decide direction from the sign.
Step 2
Why this answer is correct
The correct answer is C. \(-\sqrt{2}\) (0) के बाईं ओर है / \(-\sqrt{2}\) is to the left of (0). \(-\sqrt{2}\) is negative, so it lies to the left of (0). In exams, decide direction from the sign.
Step 3
Exam Tip
\(-\sqrt{2}\) ऋणात्मक है, इसलिए यह (0) के बाईं ओर होगा। परीक्षा में चिह्न देखकर दिशा तय करें।
\(3\sqrt{2}\) is about (4.24), so it lies between (4) and (5). In exams, you may estimate \(\sqrt{2}\) as about (1.414).
Step 2
Why this answer is correct
The correct answer is B. (4) और (5) / (4) and (5). \(3\sqrt{2}\) is about (4.24), so it lies between (4) and (5). In exams, you may estimate \(\sqrt{2}\) as about (1.414).
Step 3
Exam Tip
\(3\sqrt{2}\) लगभग (4.24) है, इसलिए यह (4) और (5) के बीच है। परीक्षा में \(\sqrt{2}\) को लगभग (1.414) मानकर अनुमान लगा सकते हैं।
Since \(\sqrt{30}\) lies between (5) and (6), \(-\sqrt{30}\) lies between (-6) and (-5). In exams, keep the negative direction in mind.
Step 2
Why this answer is correct
The correct answer is B. (-6) और (-5) / (-6) and (-5). Since \(\sqrt{30}\) lies between (5) and (6), \(-\sqrt{30}\) lies between (-6) and (-5). In exams, keep the negative direction in mind.
Step 3
Exam Tip
क्योंकि \(\sqrt{30}\) (5) और (6) के बीच है, इसलिए \(-\sqrt{30}\) (-6) और (-5) के बीच होगा। परीक्षा में ऋणात्मक दिशा को ध्यान रखें।
Since \(5^2=25\) and \(6^2=36\), \(\sqrt{27}\) lies between (5) and (6). In exams, remember nearby perfect squares.
Step 2
Why this answer is correct
The correct answer is C. (5) और (6) / (5) and (6). Since \(5^2=25\) and \(6^2=36\), \(\sqrt{27}\) lies between (5) and (6). In exams, remember nearby perfect squares.
Step 3
Exam Tip
क्योंकि \(5^2=25\) और \(6^2=36\), इसलिए \(\sqrt{27}\) (5) और (6) के बीच है। परीक्षा में निकट पूर्ण वर्गों को याद रखें।
Moving left decreases the number, so the point is \(2-\frac{3}{4}\). In exams, choose addition or subtraction according to direction.
Step 2
Why this answer is correct
The correct answer is B. \(2-\frac{3}{4}\). Moving left decreases the number, so the point is \(2-\frac{3}{4}\). In exams, choose addition or subtraction according to direction.
Step 3
Exam Tip
बाईं ओर जाने पर संख्या घटती है, इसलिए बिंदु \(2-\frac{3}{4}\) होगा। परीक्षा में दिशा के अनुसार जोड़ या घटाव चुनें।
The distance is (3.75-1.2=2.55) units. In exams, align decimal places correctly while subtracting.
Step 2
Why this answer is correct
The correct answer is C. (2.55) इकाई / (2.55) units. The distance is (3.75-1.2=2.55) units. In exams, align decimal places correctly while subtracting.
Step 3
Exam Tip
दूरी (3.75-1.2=2.55) इकाई है। परीक्षा में दशमलव स्थानों को सही मिलाकर घटाएं।
The distance is (\frac{1}{10}-\left\(-\frac{4}{5}\right\)=\frac{9}{10}) unit. In exams, subtracting a negative fraction becomes addition.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{9}{10}\) इकाई / \(\frac{9}{10}\) unit. The distance is (\frac{1}{10}-\left\(-\frac{4}{5}\right\)=\frac{9}{10}) unit. In exams, subtracting a negative fraction becomes addition.
Step 3
Exam Tip
दूरी (\frac{1}{10}-\left\(-\frac{4}{5}\right\)=\frac{9}{10}) इकाई है। परीक्षा में ऋणात्मक भिन्न जोड़ में बदल जाती है।
The distance is \(\frac{5}{6}-\frac{2}{3}=\frac{1}{6}\) unit. In exams, make denominators equal before subtracting.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{6}\) इकाई / \(\frac{1}{6}\) unit. The distance is \(\frac{5}{6}-\frac{2}{3}=\frac{1}{6}\) unit. In exams, make denominators equal before subtracting.
Step 3
Exam Tip
दूरी \(\frac{5}{6}-\frac{2}{3}=\frac{1}{6}\) इकाई है। परीक्षा में हर समान करके घटाएं।
Since \(-\sqrt{3}\) is about (-1.73), it is left of (-1). In exams, order increases from left to right.
Step 2
Why this answer is correct
The correct answer is A. \(-\sqrt{3},-1,0,\sqrt{2}\). Since \(-\sqrt{3}\) is about (-1.73), it is left of (-1). In exams, order increases from left to right.
Step 3
Exam Tip
क्योंकि \(-\sqrt{3}\) लगभग (-1.73) है, इसलिए यह (-1) से बाईं ओर है। परीक्षा में बाएं से दाएं क्रम बढ़ता है।
\(\sqrt{14}\) is about (3.74), so (3.5) is greater than (3) and less than \(\sqrt{14}\). In exams, make a rough estimate of the square root.
Step 2
Why this answer is correct
The correct answer is B. (3.5). \(\sqrt{14}\) is about (3.74), so (3.5) is greater than (3) and less than \(\sqrt{14}\). In exams, make a rough estimate of the square root.
Step 3
Exam Tip
\(\sqrt{14}\) लगभग (3.74) है, इसलिए (3.5) (3) से बड़ा और \(\sqrt{14}\) से छोटा है। परीक्षा में वर्गमूल का मोटा अनुमान लगाएं।
D. \(-\sqrt{7}\) और \(\sqrt{7}\)/\(-\sqrt{7}\) and \(\sqrt{7}\)
Step 1
Concept
From \(x^2-7=0\), \(x=\pm\sqrt{7}\). In exams, take both positive and negative square roots in a square equation.
Step 2
Why this answer is correct
The correct answer is D. \(-\sqrt{7}\) और \(\sqrt{7}\) / \(-\sqrt{7}\) and \(\sqrt{7}\). From \(x^2-7=0\), \(x=\pm\sqrt{7}\). In exams, take both positive and negative square roots in a square equation.
Step 3
Exam Tip
\(x^2-7=0\) से \(x=\pm\sqrt{7}\) मिलता है। परीक्षा में वर्ग समीकरण में धनात्मक और ऋणात्मक दोनों वर्गमूल लें।
From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 2
Why this answer is correct
The correct answer is A. (-2) और (-1) / (-2) and (-1). From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 3
Exam Tip
(4x+6=0) से \(x=-\frac{3}{2}\), जो (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का अंतराल सावधानी से पहचानें।
From (3x-7=0), \(x=\frac{7}{3}\), which lies between (2) and (3). In exams, first find the zero and then locate it.
Step 2
Why this answer is correct
The correct answer is B. (2) और (3) / (2) and (3). From (3x-7=0), \(x=\frac{7}{3}\), which lies between (2) and (3). In exams, first find the zero and then locate it.
Step 3
Exam Tip
(3x-7=0) से \(x=\frac{7}{3}\), जो (2) और (3) के बीच है। परीक्षा में पहले शून्यक निकालें फिर स्थान तय करें।
The midpoint is \(\frac{-\frac{7}{3}+\frac{2}{3}}{2}=-\frac{5}{6}\). In exams, first add and then divide by (2).
Step 2
Why this answer is correct
The correct answer is A. \(-\frac{5}{6}\). The midpoint is \(\frac{-\frac{7}{3}+\frac{2}{3}}{2}=-\frac{5}{6}\). In exams, first add and then divide by (2).
Step 3
Exam Tip
मध्य बिंदु \(\frac{-\frac{7}{3}+\frac{2}{3}}{2}=-\frac{5}{6}\) है। परीक्षा में पहले योग फिर (2) से भाग करें।
