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Which statement is correct on the number line?

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Answer and explanation

Correct answer: (-\sqrt{2}) is to the left of 0

The governing concept is the order of real numbers on a number line: negative numbers lie to the left of zero, while positive numbers lie to its right. Since \sqrt{2} is a positive irrational number, -\sqrt{2} is negative and therefore must be located to the left of 0. Thus option C is correct. Option A reverses the direction for a negative number. Option B reverses the direction for a positive number, and option D is false because \sqrt{2} is approximately 1.414, not 2. The sign alone is sufficient to decide the position here.

Related tags

Real NumbersNumber LineIrrational NumbersOrderingRepresenting Real Numbers On The Number LinePolynomialsMathematicsClass 10 Mcq

Frequently asked questions

What is the correct answer to this question?

(-\sqrt{2}) is to the left of 0

Why is this the correct answer?

The governing concept is the order of real numbers on a number line: negative numbers lie to the left of zero, while positive numbers lie to its right. Since \sqrt{2} is a positive irrational number, -\sqrt{2} is negative and therefore must be located to the left of 0. Thus option C is correct. Option A reverses the direction for a negative number. Option B reverses the direction for a positive number, and option D is false because \sqrt{2} is approximately 1.414, not 2. The sign alone is sufficient to decide the position here.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.

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