If \(s(x)=x^2-16\), which points on the number line represent its zeros?
Answer and explanation
Correct answer: Points \(-4\) and \(4\)
To find the zeros, set \(s(x)=0\): \(x^2-16=0\). Factoring gives \((x-4)(x+4)=0\), so \(x=4\) or \(x=-4\). Therefore, the corresponding points on the number line are \(-4\) and \(4\). Exam tip: for an equation of the form \(x^2=a^2\), check both values \(x=\pm a\).
Frequently asked questions
What is the correct answer to this question?
Points \(-4\) and \(4\)
Why is this the correct answer?
To find the zeros, set \(s(x)=0\): \(x^2-16=0\). Factoring gives \((x-4)(x+4)=0\), so \(x=4\) or \(x=-4\). Therefore, the corresponding points on the number line are \(-4\) and \(4\). Exam tip: for an equation of the form \(x^2=a^2\), check both values \(x=\pm a\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
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