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3 results found for "4ab" in Class 10.

यदि \(a\neq b\), तो (x-2-2(a+b)x+4ab=0) के मूलों की प्रकृति क्या होगी?

If \(a\neq b\), what will be the nature of roots of (x-2-2(a+b)x+4ab=0)?

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Correct Answer

A. वास्तविक और भिन्नReal and distinct

Step 1

Concept

Here (D=4(a-b)2). When \(a\neq b\), (D>0), so roots are real and distinct.

Step 2

Why this answer is correct

The correct answer is A. वास्तविक और भिन्न / Real and distinct. Here (D=4(a-b)2). When \(a\neq b\), (D>0), so roots are real and distinct.

Step 3

Exam Tip

यहाँ (D=4(a-b)2) है। \(a\neq b\) होने पर (D>0), इसलिए मूल वास्तविक और भिन्न होंगे।

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यदि (x-2-2(a+b)x+4ab=0) के मूल समान हैं, तो कौन सा संबंध सही है?

If (x-2-2(a+b)x+4ab=0) has equal roots, which relation is correct?

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Correct Answer

A. (a=b)

Step 1

Concept

(D=4(a+b)2-16ab=4(a-b)2). From (D=0), (a=b).

Step 2

Why this answer is correct

The correct answer is A. (a=b). (D=4(a+b)2-16ab=4(a-b)2). From (D=0), (a=b).

Step 3

Exam Tip

(D=4(a+b)2-16ab=4(a-b)2) है। (D=0) से (a=b) मिलता है।

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(4x-2-4(a+b)x+4ab=0) को सरल करने के बाद मूल क्या होंगे?

After simplifying (4x-2-4(a+b)x+4ab=0), what will be the roots?

Explanation opens after your attempt
Correct Answer

A. (x=a,b)

Step 1

Concept

Dividing the whole equation by (4) gives (x-2-(a+b)x+ab=0). In exams, removing the common factor first is easier.

Step 2

Why this answer is correct

The correct answer is A. (x=a,b). Dividing the whole equation by (4) gives (x-2-(a+b)x+ab=0). In exams, removing the common factor first is easier.

Step 3

Exam Tip

पूरे समीकरण को (4) से भाग देने पर (x-2-(a+b)x+ab=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाना आसान रहता है।

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