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With respect to \(z\), what is the degree of \(8x^5z^9-7x^3z^4+6x^2-5\)?\(z\) के सापेक्ष \(8x^5z^9-7x^3z^4+6x^2-5\) की घात (degree) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(9\)\(9\)
Consider only the powers of \(z\): \(8x^5z^9\) has \(z^9\), \(-7x^3z^4\) has \(z^4\), and \(6x^2-5\) has no \(z\), so it corresponds to \(z^0\). The highest power of \(z\) is \(9\). Hence the degree with respect to \(z\) is \(9\).केवल \(z\) की घातों पर ध्यान दें: \(8x^5z^9\) में \(z^9\) है, \(-7x^3z^4\) में \(z^4\) है, और \(6x^2-5\) में \(z\) नहीं है, इसलिए वह \(z^0\) के बराबर है। \(z\) की सबसे बड़ी घात \(9\) है। अतः \(z\) के सापेक्ष घात \(9\) है।
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