0 reads0 ratings0 helpful
With respect to \(z\), what is the degree of \(4x^5z^6-9x^2z^8+3x-1\)?\(z\) के सापेक्ष \(4x^5z^6-9x^2z^8+3x-1\) की घात (degree) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(8\)\(8\)
Degree with respect to \(z\) depends on the highest power of \(z\) appearing in the polynomial. Here, \(4x^5z^6\) has \(z^6\), \(-9x^2z^8\) has \(z^8\), and \(3x-1\) has no \(z\), so it is \(z^0\). The highest power is \(8\), so the degree with respect to \(z\) is \(8\).\(z\) के सापेक्ष घात निकालने के लिए बहुपद में दिखाई देने वाली \(z\) की सबसे बड़ी घात देखें। यहाँ \(4x^5z^6\) में \(z^6\) है, \(-9x^2z^8\) में \(z^8\) है, और \(3x-1\) में \(z\) नहीं है, इसलिए वह \(z^0\) है। सबसे बड़ी घात \(8\) है, अतः \(z\) के सापेक्ष घात \(8\) है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
