वर्गमूल सर्पिल में \(\sqrt{2600}\) का अंतराल पहचानते समय कौन-सा निष्कर्ष सही है?

While identifying the interval of \(\sqrt{2600}\) in a square root spiral, which conclusion is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(50<\sqrt{2600}<51\)

Step 1

Concept

Because \(50^2=2500\) and \(51^2=2601\). The number (2600) is less than (2601).

Step 2

Why this answer is correct

The correct answer is A. \(50<\sqrt{2600}<51\). Because \(50^2=2500\) and \(51^2=2601\). The number (2600) is less than (2601).

Step 3

Exam Tip

क्योंकि \(50^2=2500\) और \(51^2=2601\) हैं। (2600) (2601) से कम है।

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वर्गमूल सर्पिल में \(\sqrt{2600}\) का अंतराल पहचानते समय कौन-सा निष्कर्ष सही है? / While identifying the interval of \(\sqrt{2600}\) in a square root spiral, which conclusion is correct?

Correct Answer: A. \(50<\sqrt{2600}<51\). Explanation: क्योंकि \(50^2=2500\) और \(51^2=2601\) हैं। (2600) (2601) से कम है। / Because \(50^2=2500\) and \(51^2=2601\). The number (2600) is less than (2601).

Which concept should I revise for this Mathematics MCQ?

Because \(50^2=2500\) and \(51^2=2601\). The number (2600) is less than (2601).

What exam hint can help solve this Mathematics question?

क्योंकि \(50^2=2500\) और \(51^2=2601\) हैं। (2600) (2601) से कम है।