वर्गमूल सर्पिल में \(\sqrt{242}\) और \(\sqrt{256}\) की तुलना में कौन-सा कथन सही है?
Which statement is correct when comparing \(\sqrt{242}\) and \(\sqrt{256}\) in a square root spiral?
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{242}\) (15) और (16) के बीच है, \(\sqrt{256}=16\) है\(\sqrt{242}\) is between (15) and (16), \(\sqrt{256}=16\)
Concept
Because \(15^2<242<16^2\) and \(256=16^2\). Therefore \(\sqrt{242}\) is less than (16).
Why this answer is correct
The correct answer is B. \(\sqrt{242}\) (15) और (16) के बीच है, \(\sqrt{256}=16\) है / \(\sqrt{242}\) is between (15) and (16), \(\sqrt{256}=16\). Because \(15^2<242<16^2\) and \(256=16^2\). Therefore \(\sqrt{242}\) is less than (16).
Exam Tip
क्योंकि \(15^2<242<16^2\) और \(256=16^2\) है। इसलिए \(\sqrt{242}\) (16) से कम है।
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