वर्गमूल सर्पिल में \(\sqrt{99}\) और \(\sqrt{101}\) की स्थिति के बारे में सही कथन कौन-सा है?

Which statement about the positions of \(\sqrt{99}\) and \(\sqrt{101}\) in a square root spiral is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(\sqrt{99}\) (9) और (10) के बीच है, \(\sqrt{101}\) (10) और (11) के बीच है\(\sqrt{99}\) lies between (9) and (10), \(\sqrt{101}\) lies between (10) and (11)

Step 1

Concept

Since \(99<100=10^2\), \(\sqrt{99}<10\). Since (101>100), \(\sqrt{101}>10\).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{99}\) (9) और (10) के बीच है, \(\sqrt{101}\) (10) और (11) के बीच है / \(\sqrt{99}\) lies between (9) and (10), \(\sqrt{101}\) lies between (10) and (11). Since \(99<100=10^2\), \(\sqrt{99}<10\). Since (101>100), \(\sqrt{101}>10\).

Step 3

Exam Tip

\(99<100=10^2\), इसलिए \(\sqrt{99}<10\)। (101>100), इसलिए \(\sqrt{101}>10\)।

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वर्गमूल सर्पिल में \(\sqrt{99}\) और \(\sqrt{101}\) की स्थिति के बारे में सही कथन कौन-सा है? / Which statement about the positions of \(\sqrt{99}\) and \(\sqrt{101}\) in a square root spiral is correct?

Correct Answer: A. \(\sqrt{99}\) (9) और (10) के बीच है, \(\sqrt{101}\) (10) और (11) के बीच है / \(\sqrt{99}\) lies between (9) and (10), \(\sqrt{101}\) lies between (10) and (11). Explanation: \(99<100=10^2\), इसलिए \(\sqrt{99}<10\)। (101>100), इसलिए \(\sqrt{101}>10\)। / Since \(99<100=10^2\), \(\sqrt{99}<10\). Since (101>100), \(\sqrt{101}>10\).

Which concept should I revise for this Mathematics MCQ?

Since \(99<100=10^2\), \(\sqrt{99}<10\). Since (101>100), \(\sqrt{101}>10\).

What exam hint can help solve this Mathematics question?

\(99<100=10^2\), इसलिए \(\sqrt{99}<10\)। (101>100), इसलिए \(\sqrt{101}>10\)।