वर्गमूल सर्पिल में \(\sqrt{21}\) बनाने के लिए किस पिछले कर्ण का उपयोग होगा?

Which previous hypotenuse is used to make \(\sqrt{21}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{20}\)

Step 1

Concept

\(\sqrt{21}\) is formed from \(\sqrt{20}\) and a (1) unit perpendicular. The previous hypotenuse has one less number.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{20}\). \(\sqrt{21}\) is formed from \(\sqrt{20}\) and a (1) unit perpendicular. The previous hypotenuse has one less number.

Step 3

Exam Tip

\(\sqrt{20}\) और (1) इकाई लंब से \(\sqrt{21}\) बनता है। पिछले कर्ण में संख्या एक कम होती है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{21}\) बनाने के लिए किस पिछले कर्ण का उपयोग होगा? / Which previous hypotenuse is used to make \(\sqrt{21}\) in a square root spiral?

Correct Answer: B. \(\sqrt{20}\). Explanation: \(\sqrt{20}\) और (1) इकाई लंब से \(\sqrt{21}\) बनता है। पिछले कर्ण में संख्या एक कम होती है। / \(\sqrt{21}\) is formed from \(\sqrt{20}\) and a (1) unit perpendicular. The previous hypotenuse has one less number.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{21}\) is formed from \(\sqrt{20}\) and a (1) unit perpendicular. The previous hypotenuse has one less number.

What exam hint can help solve this Mathematics question?

\(\sqrt{20}\) और (1) इकाई लंब से \(\sqrt{21}\) बनता है। पिछले कर्ण में संख्या एक कम होती है।