वर्गमूल सर्पिल में \(\sqrt{100}\) और \(\sqrt{101}\) के बारे में कौन-सा विकल्प सही है?

Which option is correct about \(\sqrt{100}\) and \(\sqrt{101}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(\sqrt{100}=10\) और \(\sqrt{101}\) (10) तथा (11) के बीच है\(\sqrt{100}=10\) and \(\sqrt{101}\) is between (10) and (11)

Step 1

Concept

\(\sqrt{100}=10\) and \(10^2<101<11^2\). Therefore \(\sqrt{101}\) lies between (10) and (11).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{100}=10\) और \(\sqrt{101}\) (10) तथा (11) के बीच है / \(\sqrt{100}=10\) and \(\sqrt{101}\) is between (10) and (11). \(\sqrt{100}=10\) and \(10^2<101<11^2\). Therefore \(\sqrt{101}\) lies between (10) and (11).

Step 3

Exam Tip

\(\sqrt{100}=10\) है और \(10^2<101<11^2\) है। इसलिए \(\sqrt{101}\) (10) और (11) के बीच है।

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वर्गमूल सर्पिल में \(\sqrt{100}\) और \(\sqrt{101}\) के बारे में कौन-सा विकल्प सही है? / Which option is correct about \(\sqrt{100}\) and \(\sqrt{101}\) in a square root spiral?

Correct Answer: A. \(\sqrt{100}=10\) और \(\sqrt{101}\) (10) तथा (11) के बीच है / \(\sqrt{100}=10\) and \(\sqrt{101}\) is between (10) and (11). Explanation: \(\sqrt{100}=10\) है और \(10^2<101<11^2\) है। इसलिए \(\sqrt{101}\) (10) और (11) के बीच है। / \(\sqrt{100}=10\) and \(10^2<101<11^2\). Therefore \(\sqrt{101}\) lies between (10) and (11).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{100}=10\) and \(10^2<101<11^2\). Therefore \(\sqrt{101}\) lies between (10) and (11).

What exam hint can help solve this Mathematics question?

\(\sqrt{100}=10\) है और \(10^2<101<11^2\) है। इसलिए \(\sqrt{101}\) (10) और (11) के बीच है।