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Which hypotenuse is constructed just before (\sqrt{7}) in a square root spiral?वर्गमूल सर्पिल में (\sqrt{7}) बनाने से ठीक पहले कौन-सा कर्ण बनता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\sqrt{6})(\sqrt{6})
Adding a (1) unit perpendicular to (\sqrt{6}) gives (\sqrt{7}). The previous hypotenuse has one less number.(\sqrt{6}) में (1) इकाई लंब जोड़ने पर (\sqrt{7}) मिलता है। पिछला कर्ण हमेशा एक कम संख्या का होता है।
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