वर्गमूल सर्पिल में \(\sqrt{840}\) की संख्या-रेखा स्थिति कौन-सी है?
What is the number-line position of \(\sqrt{840}\) in a square root spiral?
Explanation opens after your attempt
B. \(28<\sqrt{840}<29\)
Concept
Because \(28^2=784\) and \(29^2=841\). The number (840) lies between them, so \(\sqrt{840}\) lies between (28) and (29).
Why this answer is correct
The correct answer is B. \(28<\sqrt{840}<29\). Because \(28^2=784\) and \(29^2=841\). The number (840) lies between them, so \(\sqrt{840}\) lies between (28) and (29).
Exam Tip
क्योंकि \(28^2=784\) और \(29^2=841\) हैं। (840) इनके बीच है, इसलिए \(\sqrt{840}\) (28) और (29) के बीच है।
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