वर्गमूल सर्पिल में \(\sqrt{840}\) की संख्या-रेखा स्थिति कौन-सी है?

What is the number-line position of \(\sqrt{840}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(28<\sqrt{840}<29\)

Step 1

Concept

Because \(28^2=784\) and \(29^2=841\). The number (840) lies between them, so \(\sqrt{840}\) lies between (28) and (29).

Step 2

Why this answer is correct

The correct answer is B. \(28<\sqrt{840}<29\). Because \(28^2=784\) and \(29^2=841\). The number (840) lies between them, so \(\sqrt{840}\) lies between (28) and (29).

Step 3

Exam Tip

क्योंकि \(28^2=784\) और \(29^2=841\) हैं। (840) इनके बीच है, इसलिए \(\sqrt{840}\) (28) और (29) के बीच है।

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वर्गमूल सर्पिल में \(\sqrt{840}\) की संख्या-रेखा स्थिति कौन-सी है? / What is the number-line position of \(\sqrt{840}\) in a square root spiral?

Correct Answer: B. \(28<\sqrt{840}<29\). Explanation: क्योंकि \(28^2=784\) और \(29^2=841\) हैं। (840) इनके बीच है, इसलिए \(\sqrt{840}\) (28) और (29) के बीच है। / Because \(28^2=784\) and \(29^2=841\). The number (840) lies between them, so \(\sqrt{840}\) lies between (28) and (29).

Which concept should I revise for this Mathematics MCQ?

Because \(28^2=784\) and \(29^2=841\). The number (840) lies between them, so \(\sqrt{840}\) lies between (28) and (29).

What exam hint can help solve this Mathematics question?

क्योंकि \(28^2=784\) और \(29^2=841\) हैं। (840) इनके बीच है, इसलिए \(\sqrt{840}\) (28) और (29) के बीच है।