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What is the degree of (x^0+9x^2-4)?बहुपद (x^0+9x^2-4) की डिग्री क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 22
Here, \(x^0=1\), so the polynomial becomes \(1+9x^2-4=9x^2-3\). The highest exponent of \(x\) with a non-zero coefficient is \(2\), so its degree is \(2\). Note that \(9\) is a coefficient, not an exponent. Exam tip: simplify constant terms first, then identify the highest power of \(x\).यहाँ \(x^0=1\) है, इसलिए बहुपद \(1+9x^2-4=9x^2-3\) बनता है। इसका शून्येतर गुणांक वाला सबसे बड़ा घातांक \(2\) है, अतः इसकी डिग्री \(2\) है। \(9\) गुणांक है, घातांक नहीं। परीक्षा टिप: पहले स्थिर पदों को सरल करें, फिर \(x\) की सबसे बड़ी घात देखें।
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