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What is the degree of (x^0+5x^2-8)?बहुपद (x^0+5x^2-8) की डिग्री क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 22
Here, \(x^0=1\), so the polynomial becomes \(1+5x^2-8=5x^2-7\). The highest exponent with a non-zero coefficient is \(2\); therefore, its degree is \(2\). The exponent \(0\) may occur in a constant term, but it is not the degree here. Exam tip: simplify like terms first, then identify the greatest exponent with a non-zero coefficient.यहाँ \(x^0=1\) होता है, इसलिए बहुपद \(1+5x^2-8=5x^2-7\) बनता है। इसका शून्येतर गुणांक वाला सबसे बड़ा घातांक \(2\) है, अतः इसकी डिग्री \(2\) है। \(0\) सबसे छोटी घात हो सकती है, डिग्री नहीं। परीक्षा टिप: पहले समान पदों को सरल करें, फिर शून्येतर गुणांक वाले सबसे बड़े घातांक को देखें।
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