What is the degree of (0x^{15}+0x^{12}+0x^4-41)?बहुपद (0x^{15}+0x^{12}+0x^4-41) की डिग्री क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (0)(0)
Terms with zero coefficients disappear and (-41) remains. It is a non-zero constant polynomial with degree (0).शून्य गुणांक वाले पद हट जाते हैं और (-41) बचता है। यह अशून्य नियतांक बहुपद है जिसकी डिग्री (0) है।
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