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What is the degree of (0x^{12}+4x^5-3x^2+8)?

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Answer and explanation

Correct answer: 5

The coefficient of \(0x^{12}\) is 0, so it is a zero term and is ignored while finding the degree. Among the remaining non-zero terms, \(4x^5\), \(-3x^2\), and \(8\), the highest exponent is 5. Therefore, the degree of the polynomial is 5. Choosing 12 would be incorrect because the coefficient of \(x^{12}\) is zero. Exam tip: Remove all terms with zero coefficients before finding the degree.

Related tags

PolynomialsDegree Of PolynomialZero CoefficientClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

5

Why is this the correct answer?

The coefficient of \(0x^{12}\) is 0, so it is a zero term and is ignored while finding the degree. Among the remaining non-zero terms, \(4x^5\), \(-3x^2\), and \(8\), the highest exponent is 5. Therefore, the degree of the polynomial is 5. Choosing 12 would be incorrect because the coefficient of \(x^{12}\) is zero. Exam tip: Remove all terms with zero coefficients before finding the degree.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Degree of a Polynomial.

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