वर्गमूल सर्पिल में \(\sqrt{288}\) का सही स्थान कौन-सा है?
What is the correct position of \(\sqrt{288}\) in a square root spiral?
Explanation opens after your attempt
B. \(16<\sqrt{288}<17\)
Concept
Because \(16^2=256\) and \(17^2=289\). The number (288) lies between them, so \(\sqrt{288}\) lies between (16) and (17).
Why this answer is correct
The correct answer is B. \(16<\sqrt{288}<17\). Because \(16^2=256\) and \(17^2=289\). The number (288) lies between them, so \(\sqrt{288}\) lies between (16) and (17).
Exam Tip
क्योंकि \(16^2=256\) और \(17^2=289\) हैं। (288) इनके बीच है, इसलिए \(\sqrt{288}\) (16) और (17) के बीच है।
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