What is the correct position of (\sqrt{288}) in a square root spiral?वर्गमूल सर्पिल में (\sqrt{288}) का सही स्थान कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (16<\sqrt{288}<17)(16<\sqrt{288}<17)
Because (16^2=256) and (17^2=289). The number (288) lies between them, so (\sqrt{288}) lies between (16) and (17).क्योंकि (16^2=256) और (17^2=289) हैं। (288) इनके बीच है, इसलिए (\sqrt{288}) (16) और (17) के बीच है।
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