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Class 9 Mathematics Number Systems Square root spiralHard

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What is the correct interval for (\sqrt{1368}) in a square root spiral?

Answer and explanation

Correct answer: (36<\sqrt{1368}<37)

(36^2=1296) and (37^2=1369). The number (1368) lies between them, so (\sqrt{1368}) lies between (36) and (37).

Related tags

Square-Root-Spiral Hard Number-Line Interval Square Root Spiral Number Systems Mathematics Class 9 Mcq

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