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Class 9MathematicsNumber SystemsSquare root spiralEasy
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What is the correct initial order of hypotenuses in a square root spiral?

Answer and explanation

Correct answer: (\sqrt{1},\sqrt{2},\sqrt{3},\sqrt{4})

The hypotenuses progress as (\sqrt{1},\sqrt{2},\sqrt{3}) and so on. Recognizing the order is useful in easy questions.

Related tags

Number-SystemsSquare-Root-SpiralSequenceSquare Root SpiralNumber SystemsMathematicsClass 9 Mcq
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10 more MCQs
  1. 1In a square root spiral, which segment is drawn at the end of the previous hypotenuse to form a new right triangle?
  2. 2In a square root spiral, what is the hypotenuse of the first right triangle made with base (1) unit and perpendicular (1) unit?
  3. 3If a perpendicular of length 1 unit is drawn at the end of a hypotenuse of length √2, what will be the length of the next hypotenuse?
  4. 4In a square root spiral, after the hypotenuse (\sqrt{3}), which length is obtained by adding a (1) unit perpendicular?
  5. 5Each new triangle in a square root spiral is of which type?
  6. 6In a square root spiral, how long is the new perpendicular side usually kept in each new triangle?
  7. 7Which theorem is mainly used to find the hypotenuse in a square root spiral?
  8. 8Why is each new 1-unit line segment drawn perpendicular to the previous hypotenuse in a square root spiral?
  9. 9Starting from (\sqrt{1}) in a square root spiral, which is the third hypotenuse?
  10. 10In a square root spiral, the line segment representing \(\sqrt{7}\) lies between which two consecutive whole numbers?
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