वर्गमूल सर्पिल में कर्णों का प्रारंभिक सही क्रम कौन-सा है?

What is the correct initial order of hypotenuses in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{1},\sqrt{2},\sqrt{3},\sqrt{4}\)

Step 1

Concept

The hypotenuses progress as \(\sqrt{1},\sqrt{2},\sqrt{3}\) and so on. Recognizing the order is useful in easy questions.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{1},\sqrt{2},\sqrt{3},\sqrt{4}\). The hypotenuses progress as \(\sqrt{1},\sqrt{2},\sqrt{3}\) and so on. Recognizing the order is useful in easy questions.

Step 3

Exam Tip

सर्पिल में कर्ण क्रम से \(\sqrt{1},\sqrt{2},\sqrt{3}\) आगे बढ़ते हैं। क्रम पहचानना आसान प्रश्नों में बहुत उपयोगी है।

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वर्गमूल सर्पिल में कर्णों का प्रारंभिक सही क्रम कौन-सा है? / What is the correct initial order of hypotenuses in a square root spiral?

Correct Answer: A. \(\sqrt{1},\sqrt{2},\sqrt{3},\sqrt{4}\). Explanation: सर्पिल में कर्ण क्रम से \(\sqrt{1},\sqrt{2},\sqrt{3}\) आगे बढ़ते हैं। क्रम पहचानना आसान प्रश्नों में बहुत उपयोगी है। / The hypotenuses progress as \(\sqrt{1},\sqrt{2},\sqrt{3}\) and so on. Recognizing the order is useful in easy questions.

Which concept should I revise for this Mathematics MCQ?

The hypotenuses progress as \(\sqrt{1},\sqrt{2},\sqrt{3}\) and so on. Recognizing the order is useful in easy questions.

What exam hint can help solve this Mathematics question?

सर्पिल में कर्ण क्रम से \(\sqrt{1},\sqrt{2},\sqrt{3}\) आगे बढ़ते हैं। क्रम पहचानना आसान प्रश्नों में बहुत उपयोगी है।