किस बिंदु तक सर्पिल बनाते समय \( \sqrt{1} \) से शुरू करके कुल (11) त्रिज्या-बिंदु मिलते हैं?
Up to which point will the spiral have (11) radius-points if it starts from \( \sqrt{1} \)?
Explanation opens after your attempt
B. \( \sqrt{11} \)
Concept
From \( \sqrt{1} \) to \( \sqrt{11} \), there are (11) points. Include the initial \( \sqrt{1} \) in counting.
Why this answer is correct
The correct answer is B. \( \sqrt{11} \). From \( \sqrt{1} \) to \( \sqrt{11} \), there are (11) points. Include the initial \( \sqrt{1} \) in counting.
Exam Tip
\( \sqrt{1} \) से \( \sqrt{11} \) तक कुल (11) बिंदु होते हैं। गिनती में आरंभिक \( \sqrt{1} \) को भी शामिल करें।
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