\(\sqrt{2}\) को संख्या रेखा पर दिखाने के लिए वर्गमूल सर्पिल से कौन-सी लंबाई कंपास में ली जाती है?

To show \(\sqrt{2}\) on the number line using a square root spiral, which length is taken in the compass?

Author: Muft Shiksha Editorial Team Published: Updated:
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Correct Answer

A. \(\sqrt{2}\) का कर्णHypotenuse of \(\sqrt{2}\)

Step 1

Concept

The hypotenuse of length \(\sqrt{2}\) is taken in the compass and an arc is drawn on the number line. This locates the point.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}\) का कर्ण / Hypotenuse of \(\sqrt{2}\). The hypotenuse of length \(\sqrt{2}\) is taken in the compass and an arc is drawn on the number line. This locates the point.

Step 3

Exam Tip

\(\sqrt{2}\) वाला कर्ण कंपास में लेकर संख्या रेखा पर चाप लगाया जाता है। इससे स्थान मिलता है।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{2}\) को संख्या रेखा पर दिखाने के लिए वर्गमूल सर्पिल से कौन-सी लंबाई कंपास में ली जाती है? / To show \(\sqrt{2}\) on the number line using a square root spiral, which length is taken in the compass?

Correct Answer: A. \(\sqrt{2}\) का कर्ण / Hypotenuse of \(\sqrt{2}\). Explanation: \(\sqrt{2}\) वाला कर्ण कंपास में लेकर संख्या रेखा पर चाप लगाया जाता है। इससे स्थान मिलता है। / The hypotenuse of length \(\sqrt{2}\) is taken in the compass and an arc is drawn on the number line. This locates the point.

Which concept should I revise for this Mathematics MCQ?

The hypotenuse of length \(\sqrt{2}\) is taken in the compass and an arc is drawn on the number line. This locates the point.

What exam hint can help solve this Mathematics question?

\(\sqrt{2}\) वाला कर्ण कंपास में लेकर संख्या रेखा पर चाप लगाया जाता है। इससे स्थान मिलता है।