वर्गमूल सर्पिल में \(\sqrt{15}\) बनाने से ठीक पहले कौन-सी लंबाई बन चुकी होगी?
Just before making \(\sqrt{15}\) in a square root spiral, which length will have already been made?
Explanation opens after your attempt
B. \(\sqrt{14}\)
Concept
\(\sqrt{14}\) will be the previous hypotenuse. Adding a (1) unit perpendicular to it gives \(\sqrt{15}\).
Why this answer is correct
The correct answer is B. \(\sqrt{14}\). \(\sqrt{14}\) will be the previous hypotenuse. Adding a (1) unit perpendicular to it gives \(\sqrt{15}\).
Exam Tip
\(\sqrt{14}\) पिछले चरण का कर्ण होगा। उसमें (1) इकाई लंब जोड़कर \(\sqrt{15}\) बनेगा।
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