वर्गमूल सर्पिल में \(\sqrt{15}\) बनाने से ठीक पहले कौन-सी लंबाई बन चुकी होगी?

Just before making \(\sqrt{15}\) in a square root spiral, which length will have already been made?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{14}\)

Step 1

Concept

\(\sqrt{14}\) will be the previous hypotenuse. Adding a (1) unit perpendicular to it gives \(\sqrt{15}\).

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{14}\). \(\sqrt{14}\) will be the previous hypotenuse. Adding a (1) unit perpendicular to it gives \(\sqrt{15}\).

Step 3

Exam Tip

\(\sqrt{14}\) पिछले चरण का कर्ण होगा। उसमें (1) इकाई लंब जोड़कर \(\sqrt{15}\) बनेगा।

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वर्गमूल सर्पिल में \(\sqrt{15}\) बनाने से ठीक पहले कौन-सी लंबाई बन चुकी होगी? / Just before making \(\sqrt{15}\) in a square root spiral, which length will have already been made?

Correct Answer: B. \(\sqrt{14}\). Explanation: \(\sqrt{14}\) पिछले चरण का कर्ण होगा। उसमें (1) इकाई लंब जोड़कर \(\sqrt{15}\) बनेगा। / \(\sqrt{14}\) will be the previous hypotenuse. Adding a (1) unit perpendicular to it gives \(\sqrt{15}\).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{14}\) will be the previous hypotenuse. Adding a (1) unit perpendicular to it gives \(\sqrt{15}\).

What exam hint can help solve this Mathematics question?

\(\sqrt{14}\) पिछले चरण का कर्ण होगा। उसमें (1) इकाई लंब जोड़कर \(\sqrt{15}\) बनेगा।