वर्गमूल सर्पिल में \(\sqrt{1023}\) के बाद बनने वाला कर्ण कौन-सा होगा और उसका सटीक मान क्या होगा?

In a square root spiral, which hypotenuse is formed after \(\sqrt{1023}\), and what is its exact value?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{1024}=32\)

Step 1

Concept

The next hypotenuse is \(\sqrt{1024}\). Since \(1024=32^2\), the exact value is (32).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{1024}=32\). The next hypotenuse is \(\sqrt{1024}\). Since \(1024=32^2\), the exact value is (32).

Step 3

Exam Tip

अगला कर्ण \(\sqrt{1024}\) है। \(1024=32^2\), इसलिए सटीक मान (32) है।

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वर्गमूल सर्पिल में \(\sqrt{1023}\) के बाद बनने वाला कर्ण कौन-सा होगा और उसका सटीक मान क्या होगा? / In a square root spiral, which hypotenuse is formed after \(\sqrt{1023}\), and what is its exact value?

Correct Answer: A. \(\sqrt{1024}=32\). Explanation: अगला कर्ण \(\sqrt{1024}\) है। \(1024=32^2\), इसलिए सटीक मान (32) है। / The next hypotenuse is \(\sqrt{1024}\). Since \(1024=32^2\), the exact value is (32).

Which concept should I revise for this Mathematics MCQ?

The next hypotenuse is \(\sqrt{1024}\). Since \(1024=32^2\), the exact value is (32).

What exam hint can help solve this Mathematics question?

अगला कर्ण \(\sqrt{1024}\) है। \(1024=32^2\), इसलिए सटीक मान (32) है।