In a square root spiral, what should be done in the next step from the point representing \(\sqrt{6}\) to obtain \(\sqrt{7}\)?

Correct answer: Draw a 1-unit perpendicular segment at the end of \(\sqrt{6}\) and take the hypotenuse

At each step, a 1-unit side is drawn perpendicular to the previous radius. Thus, hypotenuse² = \(6+1=7\), so the hypotenuse is \(\sqrt{7}\). In exams, always check the right angle.