वर्गमूल सर्पिल में (1) इकाई और (1) इकाई भुजाओं से बने समकोण त्रिभुज का कर्ण क्या होगा?

In a square root spiral, what is the hypotenuse of a right triangle with sides (1) unit and (1) unit?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{2}\)

Step 1

Concept

By Pythagoras theorem the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). The first main hypotenuse is \(\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{2}\). By Pythagoras theorem the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). The first main hypotenuse is \(\sqrt{2}\).

Step 3

Exam Tip

पाइथागोरस प्रमेय से कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पहला मुख्य कर्ण \(\sqrt{2}\) है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में (1) इकाई और (1) इकाई भुजाओं से बने समकोण त्रिभुज का कर्ण क्या होगा? / In a square root spiral, what is the hypotenuse of a right triangle with sides (1) unit and (1) unit?

Correct Answer: B. \(\sqrt{2}\). Explanation: पाइथागोरस प्रमेय से कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पहला मुख्य कर्ण \(\sqrt{2}\) है। / By Pythagoras theorem the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). The first main hypotenuse is \(\sqrt{2}\).

Which concept should I revise for this Mathematics MCQ?

By Pythagoras theorem the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). The first main hypotenuse is \(\sqrt{2}\).

What exam hint can help solve this Mathematics question?

पाइथागोरस प्रमेय से कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पहला मुख्य कर्ण \(\sqrt{2}\) है।