वर्गमूल सर्पिल में \(\sqrt{2115}\) के बाद बनने वाला कर्ण किस विशेष मान पर स्थित होगा?
In a square root spiral, the hypotenuse formed after \(\sqrt{2115}\) will be located at which special value?
Explanation opens after your attempt
D. \(\sqrt{2116}=46\)
Concept
The next hypotenuse is \(\sqrt{2116}\). Since \(2116=46^2\), it is located exactly at (46).
Why this answer is correct
The correct answer is D. \(\sqrt{2116}=46\). The next hypotenuse is \(\sqrt{2116}\). Since \(2116=46^2\), it is located exactly at (46).
Exam Tip
अगला कर्ण \(\sqrt{2116}\) है। \(2116=46^2\), इसलिए यह ठीक (46) पर स्थित है।
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